JavaScript - Throw Exception containing variable name -

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• how execute javascript function when have name string 29 answers

how can throw exception using variable within exception name during throw new statement?

i have list of exceptions i'm trying throw depending on whether or not 1 variable 0 in length. name of exception, example, contains variable name.

works

if (x.length === 0) {     throw new noxexception(); }  if (y.length === 0) {     throw new noyexception(); }  if (z.length === 0) {     throw new nozexception(); } 

doesn't work

var x = 'oh'; var y = 'hai'; var z = '';  // contains "nozexception" var ex = "no" + ((x.length != 0) ? ((y.length != 0) ? 'z' : 'y') : 'x') + "exception";  // throwing ex gives error throw new ex(); 

you trying convert string function , create new instance of variable, won't work.

there ways function corresponding string: how turn string javascript function call?

but better way go first if statement, or convert switch.

for global variable:

// set in global scope, not in scope of else. var noxexception = function () { ... }  var variable = "no" + getmissing() + "exception"; throw new window[variable]() 

for variable that's stored within another's scope:

var exceptions = {} exceptions.noxexception = function () { ... }  var variable = "no" + getmissing() + "exception"; throw new exceptions[variable]() // alternatively throw new window['exceptions'][variable]()