Open xml file, find url within, open link and search for value - python lxml -

i opening xml file, lxml, , doing lot of editing before saving out new xml file, working fine. within opened xml, have url links web page. in webpage values record , use in open xml. have searched can't find start.

kind regards.

update -

i using below code gleam url xml, , working. can read page data variable, prints fine:

url = tree.find("//video/products/product/read_only_info/read_only_value[@key='storeurl-gb']") if url not none:     url = url.text     data = urllib2.urlopen(url)     data = data.read()     print data 

how can find particular string buried in web page, here piece of web page data want get:

<div id="content">    <div class="padder">      <div id="title" class="intro">       <div class="left">         <h1>this title</h1>         &nbsp;&nbsp;<span rating-system="bbfc" rating-id="37" class="content-rating">15</span>         <h2>this more text</h2>       </div>       <div class="right">         <a href="https://rthuere.erwerwer.ghty4e.fdfsdf.com" class="view-more">view more in sci-fi &amp; fantasy</a>        </div> 

i need value "view more in sci-fi & fantasy" or whatever other value there.

kind regards.

if want text of a-nodes, can using beautifulsoup:

soup = beautifulsoup(html_page) link in soup.findall('a'):     print link.text 

does answer question?