javascript - Use part of regexp result set to make match -

is posible use sub result regexp make entire regexp, consider snippet:

var ret = "{hello} {world}"; ret = ret.replace(/(^|[^{}])(\{|\})([^{}]|$)/g, '$1$2$2$3'); ret; // {{hello}} {{world}} 

but when put }{ above regexp fail, makes sense cause i'm testing against none of }{ or beginning of string , 1 of {} , again none of {} or end of string:

var ret = "{hello}{world}"; ret = ret.replace(/(^|[^{}])(\{|\})([^{}]|$)/g, '$1$2$2$3'); ret; // {{hello}{world}} 

is posible use frist result set make second , again make third:

/(^|[^{}])($1)([^{}]|$)/g, '$1$2$2$3' //         $1 - or 

i'm avare of can use multiply ·replace method calls cool have one.

thanks

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don't consider readability of code.

does 1 regexp work you?

ret.replace(/[{]+(.*?)[}]+/g, '{{$1}}') 

p.s.: not sure trying achieve.