c++ - Can we achieve polymorphism through const function? -

can achieve polymorphism through const function? mean function a() , function a()const behave polymorphically?

void func(int a){} void func(int a)const {} 

answer . can overload !!

#include<iostream> using namespace std;  class test { protected:     int x; public:     test (int i):x(i) { }     void fun() const     {         cout << "fun() const called " << endl;     }     void fun()     {         cout << "fun() called " << endl;     } };  int main() {     test t1 (10);     const test t2 (20);     t1.fun();     t2.fun();     return 0; } 

output: above program compiles , runs fine, , produces following output.

fun() called fun() const called 

the 2 methods ‘void fun() const’ , ‘void fun()’ have same signature except 1 const , other not. also, if take closer @ output, observe that, ‘const void fun()’ called on const object , ‘void fun()’ called on non-const object. c++ allows member methods overloaded on basis of const type. overloading on basis of const type can useful when function return reference or pointer. can make 1 function const, returns const reference or const pointer, other non-const function, returns non-const reference or pointer.