How to make jquery radio button function run on page load? -

edit: replies! unfortunately using .trigger('change') or .change() manually run event doesn't work properly. if user changes value of 1 set of radio buttons, doesn't change other, maths doesn't add up. other suggestions?

i have this form

it works want to, jquery function run on page load when user changes radio button selection. how this?

var price=$("input[name='courierrepairprice']").val(); price = number(price.replace(/[^0-9\.]+/g,"")); var postage_out=0; var postage_in=0 $("input[name='outwardpostage']").change(function() {    postage_out=$(this).val();    tot_price=parsefloat(price,10)+parsefloat(postage_out,10)+parsefloat(postage_in,10)    tot_price=tot_price.tofixed(2)     $('.tot_price').text('£'+tot_price);  }); $("input[name='returnpostage']").change(function() {    postage_in=$(this).val();       tot_price=parsefloat(price,10)+parsefloat(postage_out,10)+parsefloat(postage_in,10)    tot_price=tot_price.tofixed(2)    $('.tot_price').text('£'+tot_price); }); 

use .trigger('change') or .change() manually simulate event

var price=$("input[name='courierrepairprice']").val(); price = number(price.replace(/[^0-9\.]+/g,"")); var postage_out=0; var postage_in=0;  function calculate(){     console.log('calc', price, postage_out, postage_in)     var tot_price = price + postage_out + postage_in;     tot_price=tot_price.tofixed(2)      $('.tot_price').text('£' + tot_price); }  $("input[name='outwardpostage']").change(function() {     postage_out = parsefloat($(this).val());     calculate(); }).filter(':checked').trigger('change'); $("input[name='returnpostage']").change(function() {     postage_in =  parsefloat($(this).val());        calculate(); }).filter(':checked').trigger('change'); 

demo: fiddle