c++ - Write int value into an array of bytes -

i have array : byte set[6] = { 0xa8,0x12,0x84,0x03,0x00,0x00, } , need insert value : "" int value = 1200; "" ....on last 4 bytes. practically convert int hex , write inside array... possible ?

i have bitconverter::getbytes function, that's not enough.

thank you,

to answer original quesion: sure can. sizeof(int) == 4 , sizeof(byte) == 1.

but i'm not sure mean "converting int hex". if want hex string representation, you'll better off using 1 of standard methods of doing it. example, on last line use std::hex print numbers hex.

here solution you've been asking , little more (live example: http://codepad.org/rsmzngul):

#include <iostream>  using namespace std;  int main() {     const int value = 1200;     unsigned char set[] = { 0xa8,0x12,0x84,0x03,0x00,0x00 };      (const unsigned char* c = set; c != set + sizeof(set); ++c)    {         cout << static_cast<int>(*c) << endl;     }      cout << endl << "putting value array:" << endl;     *reinterpret_cast<int*>(&set[2]) = value;      (const unsigned char* c = set; c != set + sizeof(set); ++c)    {         cout << static_cast<int>(*c) << endl;     }      cout << endl << "printing int's bytes 1 one: " << endl;     (int bytenumber = 0; bytenumber != sizeof(int); ++bytenumber) {         const unsigned char onebyte = reinterpret_cast<const unsigned char*>(&value)[bytenumber];         cout << static_cast<int>(onebyte) << endl;     }      cout << endl << "printing value hex: " << hex << value << std::endl; } 

upd: comments question: 1. if need getting separate digits out of number in separate bytes, it's different story. 2. little vs big endianness matters well, did not account in answer.